{1}: | F_{def} = C * M_{p} * (D/t)^{½} |
C | = | factor related to jaw shape of the shear and extend of deformation | |
M_{p} | = | plastic moment per unity of length | |
= | σ_{y} * ( t^{2} / 4 ) | ||
t | = | wall thickness | |
σ_{y} | = | yield stress | |
D | = | tube diameter |
F_{cut} > F_{def} |
{2}: | F_{max} = 55 * M_{p} * (D/t)^{½} |
F_{max} > 55 * M_{p} * (D/t)^{½} |
{3}: | F_{shear} = A * 0.8 * σ_{t} |
F_{shear} | load required for shearing shear | ||
A | = | area of material between the blades of the shear | |
σ_{t} | = | tensile strength of material to be cut |
{4}: | A_{crosss-sectional} < 0.8 * F_{cut} / ( 0.8 * σ_{t} ) |